50g^2+40g+8=0

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Solution for 50g^2+40g+8=0 equation: 



50g^2+40g+8=0

a = 50; b = 40; c = +8;
Δ = b2-4ac
Δ = 402-4·50·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$g=\frac{-b}{2a}=\frac{-40}{100}=-2/5$

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